OK...Where i've written 192.168.x.x what i suppose i shoudl have written would have been 192.168.x.y where x is your chosen third octet (which would not be the same in every network hence the wildcard element) and y are the host bits. So no. What i meant was a class C network.
With regards to your /21 subnetted network. This fellow has suggested that he's going to use 192.168.100.0 for his server IP Address....i doubt he has knowledge of subnetting hence why i simplified down to just /24 networks. I could have gone all out and started asking how many hosts he requires and gone into VLSM but I didn't think that appropriate. Would you??
Also RE: 192.168 being a valid class B network, ok yes point made and taken but, private address ranges as dictated by IANA in RFC 1918 suggest that you should not be using 192.168.whatever networks as class b private ranges but instad 172.16. networks. So if i was talking about a class B private network i wouldn't be using 192.168.x.y would i??
Joe
On 05/03/2008, Andy Smith <andy@lug.org.uk> wrote:
Hi Joe,
On Wed, Mar 05, 2008 at 11:30:03AM +0000, Joe Zambon wrote:
> 192.168.100.0 is a network ID for a Class C network of 192.168.x.x.
192.168.*.* would describe a "class B" or a /16 network. A "class
C" network is a /24, just the last octet.
> You can't assign your server that address (or any machine for that
> matter).
Yes you can. Why do you think you can't? Whether it is a good idea
is another matter (it's not), but 192.168.100.0 would be a valid
host address in a /16 (class B) network, or in fact in the /21 that
starts at 192.168.96.0/21.
Cheers,
Andy
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