[Staffslug] Complex Factors Of Primes

I'm surprised at you fellas: The whole point is that "i" or "j" is the Square Root of Minus One. Thus minus i squared equals Plus One. So: (2+i)*(2-i) = 4+1 = 5 (3+2i)*(3-2i) = 9+4 =13 Quaternions have 3 different square roots of -1, called i, j, k, and they too have Complex Conjugates like Complex Numbers. The Imaginary Components i, j, k then gave us the idea of Vectors. Divide two Vectors and you get a Quaternion. Faictz Ce Que Vouldras: Frank Mitchell